How do you simplify $(3x^2+17x-6)/(x^3-36x)$ ?

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Answer 1 · 2015-09-24T04:17:13

$(3x^2+17x-6)/(x^3-36x)=(3x-1)/(x(x-6))$

First of all you are going to need to factorise both numerator and denominator.

$(3x^2+17x-6)/(x^3-36x)=((3x-1)(x+6))/(x(x-6)(x+6))$

Then you will be able to cancel out the common factor of x+6 which yields:

$(3x^2+17x-6)/(x^3-36x)=(3x-1)/(x(x-6))$

How do you simplify (3x^2+17x-6)/(x^3-36x)(3x^2+17x-6)/(x^3-36x)?