How do you simplify $3xy^2z^4 div 9x^2yz^2$ ?

Question

1905 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-01-10T15:01:19

$= color(blue)( (x^(-1) y^(1) z^(2))/3$

$(3xy^2z^4)/(9x^2yz^2)$

$= (3/9) (x^1y^2z^4)/(x^2y^1z^2)$

As per property :
$color(blue)(a^m/a^n = a^((m-n))$

Applying the above to exponents of $x ,y$ and $z$

$= (3/9) x^((1-2)) y^((2-1)) z^((4-2))$

$= (3/9) x^(-1) y^(1) z^(2)$

$= (cancel3/cancel9) x^(-1) y^(1) z^(2)$

$= color(blue)( (x^(-1) y^(1) z^(2))/3$

How do you simplify 3xy^2z^4 div 9x^2yz^23xy^2z^4 div 9x^2yz^2?