How do you simplify $(3y)/(3y^2-6y)$ ?

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Answer 1 · 2018-04-06T04:15:05

$=1/(y-2)$

$(3y)/(3y^2-6y)$

$=(3y)/(3y(y-2))$ factorise the denominator, HCF $=3y$

$=1/(y-2)$ divide numerator and denominator by $3y$

Answer 2 · 2018-04-06T05:13:00

$1/(y-2)$

$(3y)/(3y^2-6y)$

First, we factor the bottom:
$(3y)/(3y(y-2)$

Since both the numerator and denominator are multiplied by $3y$ , we can cross that out:
$(cancel(3y))/(cancel(3y)(y-2))$

So the final answer is:
$1/(y-2)$

How do you simplify (3y)/(3y^2-6y)(3y)/(3y^2-6y)?