How do you simplify $4^n/(3^(n-1))$ ?

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Answer 1 · 2017-07-20T18:02:23

See a solution process below:

Multiply the expression by $1$ or $3/3$ :

$3/3 * 4^n/3^(n - 1) = (3 * 4^n)/(3 * 3^(n-1)) = (3 * 4^n)/(3^1 * 3^(n-1)) =$

$(3 * 4^n)/(3^(1+n-1)) = (3 * 4^n)/3^n = 3*4^n/3^n = 3(4/3)^n$

How do you simplify 4^n/(3^(n-1))4^n/(3^(n-1))?