How do you simplify $(44x^4y^2)/(32x^4y^-4)$ ?

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Answer 1 · 2018-07-08T06:23:21

$(11y^6)/8$

Given: $(44x^4y^2)/(32x^4y^-4)$

Use the exponent rules: $x^m/x^n = x^(m-n); " "1/a^-n = a^n$

Divide both the numerator and denominator by $4$ :

$(44cancel(x^4)y^2)/(32cancel(x^4)y^-4) = (11y^(2 --4))/8 = (11y^6)/8$

How do you simplify (44x^4y^2)/(32x^4y^-4)(44x^4y^2)/(32x^4y^-4)?