How do you simplify $(\frac{4 a^{3} b}{a^{2} b^{3}}) \cdot (\frac{3 b^{2}}{2 a^{2} b^{4}})$ $((4a^3b)/(a^2b^3))*((3b^2)/(2a^2b^4))$ ?

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How do you simplify $(\frac{4 a^{3} b}{a^{2} b^{3}}) \cdot (\frac{3 b^{2}}{2 a^{2} b^{4}})$ $((4a^3b)/(a^2b^3))*((3b^2)/(2a^2b^4))$ ?

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Answer 1 · 2015-04-04T16:00:59

$\frac{6}{a b^{4}}$ $6/(ab^4)$

Exponents with the same base would add on multiplication = $\frac{12}{2}$ $12/2$ $\frac{a^{3} b^{3}}{a^{4} b^{7}}$ $(a^3 b^3)/(a^4 b^7)$

= $\frac{6}{a b^{4}}$ $6/(ab^4)$ [exponents in the numerator being lesser than those in the denominator, on division these would subtract from the greater exponents. This would result in the simplification being with positive exponents.]

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How do you simplify $(\frac{4 a^{3} b}{a^{2} b^{3}}) \cdot (\frac{3 b^{2}}{2 a^{2} b^{4}})$ $((4a^3b)/(a^2b^3))*((3b^2)/(2a^2b^4))$ ?

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How do you simplify $(\frac{4 a^{3} b}{a^{2} b^{3}}) \cdot (\frac{3 b^{2}}{2 a^{2} b^{4}})$ $((4a^3b)/(a^2b^3))*((3b^2)/(2a^2b^4))$ ?