Question

How do you simplify `(4c^2+12c+9)/(2c^2-11c-21)`?

Answer 1

Factoring the numerator and denominator and then cancelling common terms gives:
`color(white)("XXXX")` `(2c+3)/(c-7)`

Explanation:

`(4c^2+12c+9)/(2c^2-11c-21)`

`color(white)("XXXX")` `= ((2c+3)(2c+3))/((2c+3)(c-7))`

`color(white)("XXXX")` `= (2c+3)/(c-7)`