How do you simplify $(4k^3m^2)^3/(5k^2m^-3)^-2$ ?

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Answer 1 · 2017-05-18T13:23:21

$1600 k^(13)$

We have: $frac((4 k^(3) m^(2))^(3))((5 k^(2) m^(- 3))^(- 2)$

Using the laws of exponents:

$= frac(64 k^(9) m^(6))(frac(1)(25) cdot k^(- 4) m^(6))$

$= frac(64)(frac(1)(25)) cdot k^(9 - (- 4)) cdot m^(6 - 6)$

$= (64 times 25) k^(9 + 4) m^(0)$

$= 1600 k^(13) times 1$

$= 1600 k^(13)$

How do you simplify (4k^3m^2)^3/(5k^2m^-3)^-2(4k^3m^2)^3/(5k^2m^-3)^-2?