How do you simplify $((4n)/(2n^2))^3$ ?

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Answer 1 · 2015-10-27T04:23:27

Here,

First you can open the bracket and multiply the power of n with 3 both in the numerator and denominator.

= $((4n)/(2n^2))^3$

= $((4^3n^3)/(2^3n^6))$

Now you can cancel the three n and 8 as it is present in both numerator and denominator.

= $((64*n*n*n )/(8*n*n*n*n*n*n))$

= $8/n^3$

How do you simplify ((4n)/(2n^2))^3((4n)/(2n^2))^3?