How do you simplify $4 n^{- 4}$ $4n^-4$ and write it using only positive exponents?

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Answer 1 · 2017-12-22T00:26:07

$\frac{4}{n^{4}}$ $4/n^4$

We use the property that $a^{- b} = \frac{1}{a^{b}}$ $a^(-b)=1/a^b$ , so:

$4 n^{- 4} = 4 \cdot (\frac{1}{n^{4}}) = \frac{4}{n^{4}}$ $4n^-4=4*(1/n^4)=4/n^4$

Answer 2 · 2017-12-22T00:28:35

$4 n^{- 4} = \frac{4}{n^{4}}$ $4n^(-4)=color(blue)(4/(n^4))$

Remember that in general
$XXX a^{- b} = \frac{1}{a^{b}}$ $color(white)("XXX")a^(-b)=1/(a^b)$

$n^{- 4} = 4 \cdot n^{- 4}$ $n^(-4)=4 * n^(-4)$

$XX = 4 \cdot \frac{1}{n^{4}}$ $color(white)("XX")=4 * 1/(n^4)$

$XX = \frac{4}{n^{4}}$ $color(white)("XX")=4/(n^4)$

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