How do you simplify ${(\frac{4 x^{- 2}}{5 y^{- 3}})}^{- 3}$ $((4x^-2)/(5y^-3))^-3$ ?

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How do you simplify ${(\frac{4 x^{- 2}}{5 y^{- 3}})}^{- 3}$ $((4x^-2)/(5y^-3))^-3$ ?

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Answer 1 · 2016-04-30T05:55:11

$= \frac{125}{64} \times \frac{x^{6}}{y^{9}}$ $=125/64xxx^6/y^9$

Explanation:

${(\frac{4 x^{- 2}}{5 y^{- 3}})}^{- 3} = \frac{4^{- 3} \cdot x^{(- 2) \cdot (- 3)}}{5^{- 3} \cdot y^{(- 3) \cdot (- 3)}} = \frac{5^{3}}{4^{3}} \times \frac{x^{6}}{y^{9}} = \frac{125}{64} \times \frac{x^{6}}{y^{9}}$ $((4x^-2)/(5y^-3))^-3=(4^-3*x^((-2)*(-3)))/(5^-3*y^((-3)*(-3)))=5^3/4^3xxx^6/y^9=125/64xxx^6/y^9$

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How do you simplify ${(\frac{4 x^{- 2}}{5 y^{- 3}})}^{- 3}$ $((4x^-2)/(5y^-3))^-3$ ?

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