How do you simplify $(5 c^{- 4}) (- 4 m^{2} c^{8})$ $(5c^(-4))(-4m^(2)c^(8))$ ?

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Answer 1 · 2015-10-08T10:30:00

$- 20 m^{2} c^{4}$ $-20 m^2c^4$

Key to solving is that: $c^{- 4} = \frac{1}{c^{4}}$ $c^(-4) = 1/(c^(4))$

Rewrite $(5 c^{- 4}) (- 4 m^{2} c^{8})$ $(5c^(-4))(-4m^2c^8)$ as:

$\frac{5}{c^{4}} \times (- 4 m^{2} c^{8})$ $5/(c^4) times (-4m^2c^8)$

Giving: $(5 \times (- 4) m^{2}) \times \frac{c^{8}}{c^{4}}$ $( 5 times (-4)m^2) times (c^8)/(c^4)$ .....( 1 )

But $\frac{c^{8}}{c^{4}} = c^{4}$ $(c^8)/(c^4) = c^4$ ......( 2 )

Substituting ( 2 ) in ( 1 ) gives

$- 20 m^{2} c^{4}$ $-20 m^2c^4$

How do you simplify (5c^(-4))(-4m^(2)c^(8))(5c−4)(−4m2c8)(5c^(-4))(-4m^(2)c^(8))?