How do you simplify $\frac{{(6 a^{- 1} b)}^{2}}{{(b^{2})}^{4}}$ $(6a^-1 b)^2/(b^2)^4$ ?

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How do you simplify $\frac{{(6 a^{- 1} b)}^{2}}{{(b^{2})}^{4}}$ $(6a^-1 b)^2/(b^2)^4$ ?

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Answer 1 · 2015-05-08T23:13:29

$\frac{{(6 a^{- 1} b)}^{2}}{{(b^{2})}^{4}}$ $(6a^(-1)b)^2/(b^2)^4$
^2
$= (\frac{6^{2}}{1}) \cdot ⎛ ⎝ \frac{{(a^{- 1})}^{2}}{1} ⎞ ⎠ \cdot (\frac{b^{2}}{{(b^{2})}^{4}})$ $= (6^2/1) * ((a^(-1))^2/1) *( (b^2)/(b^2)^4)$

$= 6^{2} \cdot \frac{1}{a^{2}} \cdot \frac{1}{{(b^{2})}^{3}}$ $= 6^2*1/a^2*1/(b^2)^3$

$= \frac{36}{a^{2} b^{6}}$ $= 36/(a^2b^6)$

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How do you simplify $\frac{{(6 a^{- 1} b)}^{2}}{{(b^{2})}^{4}}$ $(6a^-1 b)^2/(b^2)^4$ ?

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How do you simplify $\frac{{(6 a^{- 1} b)}^{2}}{{(b^{2})}^{4}}$ $(6a^-1 b)^2/(b^2)^4$ ?