How do you simplify #(6a^-1 b)^2/(b^2)^4#? Algebra Exponents and Exponential Functions Exponential Properties Involving Quotients 1 Answer Alan P. May 8, 2015 #(6a^(-1)b)^2/(b^2)^4# ^2 #= (6^2/1) * ((a^(-1))^2/1) *( (b^2)/(b^2)^4)# #= 6^2*1/a^2*1/(b^2)^3# #= 36/(a^2b^6)# Answer link Related questions What is the quotient of powers property? How do you simplify expressions using the quotient rule? What is the power of a quotient property? How do you evaluate the expression #(2^2/3^3)^3#? How do you simplify the expression #\frac{a^5b^4}{a^3b^2}#? How do you simplify #((a^3b^4)/(a^2b))^3# using the exponential properties? How do you simplify #\frac{(3ab)^2(4a^3b^4)^3}{(6a^2b)^4}#? Which exponential property do you use first to simplify #\frac{(2a^2bc^2)(6abc^3)}{4ab^2c}#? How do you simplify #(x^5y^8)/(x^4y^2)#? How do you simplify #[(2^3 *-3^2) / (2^4 * 3^-2)]^2#? See all questions in Exponential Properties Involving Quotients Impact of this question 1174 views around the world You can reuse this answer Creative Commons License