How do you simplify $(6f^-2 g^3 h^5 )/(54f^-2 g^-5 h^3)$ ?

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Answer 1 · 2018-05-29T13:23:12

$(g^8h^2)/9$

Simplify all like terms:

$6/54=1/9$

$f^-2/(f^-2)=f^(-2- -2)=f^(-2+2)=f^0=1$

$g^3/(g^-5)=g^(3- -5)= g^(3 + 5) = g^8$

$h^5/h^3=h^(5-3)=h^2$

Put these together:

$(g^8h^2)/9$

How do you simplify (6f^-2 g^3 h^5 )/(54f^-2 g^-5 h^3)(6f^-2 g^3 h^5 )/(54f^-2 g^-5 h^3)?