How do you simplify $\frac{7 x^{2} - 7}{{(x - 1)}^{2}}$ $(7x^2 - 7)/(x - 1)^2$ ?

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Answer 1 · 2015-04-08T23:16:20

Factor the numerator and denominator and "cancel" terms the occur in both

$\frac{7 x^{2} - 7}{{(x - 1)}^{2}}$ $(7x^2-7)/((x-1)^2)$

$= ((7)cancel((x-1))(x+1))/(cancel((x-1))(x-1))$

$= 7 (x+1)/(x-1)$

How do you simplify (7x^2 - 7)/(x - 1)^27x2−7(x−1)2(7x^2 - 7)/(x - 1)^2?