How do you simplify $7 x^{3} \frac{{(2 x^{2})}^{2}}{10 x^{5}}$ $7x^3(2x^2)^2/(10x^5)$ ?

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How do you simplify $7 x^{3} \frac{{(2 x^{2})}^{2}}{10 x^{5}}$ $7x^3(2x^2)^2/(10x^5)$ ?

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Answer 1 · 2015-10-02T21:56:17

It is $7 x^{3} \frac{{(2 x^{2})}^{2}}{10 x^{5}} = 7 x^{3} \cdot \frac{4 x^{4}}{10 x^{5}} = \frac{28 \cdot x^{7}}{10 x^{5}} = \frac{14}{5} \cdot x^{2}$ $7x^3(2x^2)^2/(10x^5)=7x^3*(4x^4)/(10x^5)=(28*x^7)/(10x^5)=14/5*x^2$

Answer 2 · 2015-10-02T23:43:59

The answer is $\frac{14 x^{2}}{5}$ $(14x^2)/5$ .

Explanation:

Simplify $7 x^{3} \frac{{(2 x^{2})}^{2}}{10^{5}}$ $7x^3(2x^2)^2/(10^5)$ to $\frac{(7 x^{3}) {(2 x^{2})}^{2}}{10 x^{5}}$ $((7x^3)(2x^2)^2)/(10x^5)$ .

$\frac{(7 x^{3}) {(2 x^{2})}^{2}}{10 x^{5}}$ $((7x^3)(2x^2)^2)/(10x^5)$

Apply the exponent rule ${(a^{m})}^{n} = a^{m \cdot n}$ $(a^m)^n=a^(m*n)$

$\frac{(7 x^{3}) (4 x^{4})}{10 x^{5}}$ $((7x^3)(4x^4))/(10x^5)$

Apply the exponent rule $a^{m} \times a^{n} = a^{m + n}$ $a^mxxa^n=a^(m+n)$ .

$\frac{28 x^{3 + 4}}{10 x^{5}} =$ $(28x^(3+4))/(10x^5)=$

$\frac{28 x^{7}}{10 x^{5}}$ $(28x^7)/(10x^5)$

Apply the exponent rule $\frac{a^{m}}{a^{n}} = a^{m - n}$ $a^m/a^n=a^(m-n)$ .

$\frac{28 x^{7 - 5}}{10} =$ $(28x^(7-5))/10=$

$\frac{28 x^{2}}{10}$ $(28x^2)/10$

Reduce $\frac{28}{10}$ $28/10$ to $\frac{14}{5} =$ $14/5=$ .

$\frac{14 x^{2}}{5}$ $(14x^2)/5$

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How do you simplify $7 x^{3} \frac{{(2 x^{2})}^{2}}{10 x^{5}}$ $7x^3(2x^2)^2/(10x^5)$ ?

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How do you simplify $7 x^{3} \frac{{(2 x^{2})}^{2}}{10 x^{5}}$ $7x^3(2x^2)^2/(10x^5)$ ?