How do you simplify $\frac{7 x^{7} y^{8}}{21 x^{10} y^{2}}$ $(7x^7y^8)/(21x^10y^2)$ ?

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Answer 1 · 2016-11-07T18:42:20

$\frac{x^{- 3} y^{6}}{3}$ $(x^-3y^6)/3$ or $\frac{y^{6}}{3 x^{3}}$ $y^6/(3x^3)$

Grouping like terms gives:

$\frac{7}{21} x^{7 - 10} y^{8 - 2}$ $7/21 x^(7 - 10)y^(8-2)$

$\frac{1}{3} x^{- 3} y^{6}$ $1/3 x^-3y^6$

$\frac{x^{- 3} y^{6}}{3}$ $(x^-3y^6)/3$ or $\frac{y^{6}}{3 x^{3}}$ $y^6/(3x^3)$

How do you simplify (7x^7y^8)/(21x^10y^2)7x7y821x10y2(7x^7y^8)/(21x^10y^2)?