How do you simplify $(8 a + 1) (2 a - 3) - {(4 a - 5)}^{2}$ $(8a + 1) ( 2a - 3) - ( 4a - 5)^{2}$ ?

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How do you simplify $(8 a + 1) (2 a - 3) - {(4 a - 5)}^{2}$ $(8a + 1) ( 2a - 3) - ( 4a - 5)^{2}$ ?

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Answer 1 · 2018-04-23T12:47:28

I use FOIL: $(8 a + 1) (2 a - 3) - {(4 a - 5)}^{2}$ $(8a+1)(2a -3)-(4a -5)^2$ $= 16 a^{2} - 24 a + 2 a - 3 - (16 a^{2} - 40 a + 25)$ $= 16 a^2 - 24 a + 2a -3 - (16a^2 - 40a + 25)$ $= 18 a - 28$ $=18 a - 28$

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How do you simplify $(8 a + 1) (2 a - 3) - {(4 a - 5)}^{2}$ $(8a + 1) ( 2a - 3) - ( 4a - 5)^{2}$ ?

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How do you simplify $(8 a + 1) (2 a - 3) - {(4 a - 5)}^{2}$ $(8a + 1) ( 2a - 3) - ( 4a - 5)^{2}$ ?