How do you simplify $8 n^{- 1}$ $8n^-1$ and write it using only positive exponents?

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Answer 1 · 2017-02-10T13:57:33

See the entire simplification process below:

We will use these two rules for exponents to complete this problem:

$x^{a} = \frac{1}{x^{- a}}$ $x^color(red)(a) = 1/x^color(red)(-a)$

$a^{1} = a$ $a^color(red)(1) = a$

$8 n^{- 1} = \frac{8}{n^{- - 1}} = \frac{8}{n^{1}} = \frac{8}{n}$ $8n^color(red)(-1) = 8/n^color(red)(- -1) = 8/n^color(red)(1) = 8/n$ #

How do you simplify 8n−18n^-1 and write it using only positive exponents?