How do you simplify $(9s+72)/(s^2-2s-80)$ ?

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Answer 1 · 2017-01-02T13:26:05

$(9s+72)/(s^2-2s-80)=color(green)(9/(s-10))$

$9s+72=color(blue)(9(s+8))$

$s^2-2x-80=color(blue)((s+8)(s-10))$

Therefore
$(9s+72)/(s^2-2s-80)=color(blue)((9cancel(""(s+8)))/(cancel(""(s+8))(s-10)))=color(green)(9/(s-10))$

How do you simplify (9s+72)/(s^2-2s-80)(9s+72)/(s^2-2s-80)?