How do you simplify $(a^-1b^2)/(ab) times (a^2b^3)/b^-2$ ?

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Answer 1 · 2016-09-04T09:32:52

$b^6$

$(color(red)(a^-1)b^2)/(ab) times (a^2b^3)/color(blue)(b^-2)$

Use the law of indices $x^-m = 1/x^m$ to get rid of the negative indices.

= $(b^2)/(color(red)(a)ab) xx (a^2b^3color(blue)(b^2 ))/1" "larr"now simplify"$

= $(a^2b^7)/(a^2b)$

= $b^6$

How do you simplify (a^-1b^2)/(ab) times (a^2b^3)/b^-2(a^-1b^2)/(ab) times (a^2b^3)/b^-2?