How do you simplify and find the excluded value of (2b )/ (6b-2)2b6b−2?

1 Answer
Jim G.
Jun 16, 2017

b/(3b-1)b3b−1

Explanation:

"factorise the denominator by taking out 2 as a "factorise the denominator by taking out 2 as a
color(blue)"common factor"common factor

rArr(2b)/(2(3b-1))⇒2b2(3b−1)

=(cancel(2)^1 b)/(cancel(2)^1(3b-1))larr" cancelling"

"excluded values are any values of b that make the "
"denominator equal to zero as this would make the"
"fraction "color(blue)"undefined"

rArr"solve " 3b-1=0rArrb=1/3

rArrb=1/3" is the excluded value"

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