How do you simplify and find the excluded value of $(d+7)/(d^2-49)$ ?

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Answer 1 · 2016-10-01T08:04:21

$1/(d-7)$ and $d!=+-7$

The first approach with algebraic fractions is to see if you can find factors.

$(d+7)/(d^2-49) " "larr$ difference of squares

$=((d+7))/((d+7)(d-7))" "larr d!=+-7$

$cancel((d+7))/(cancel((d+7))(d-7)$

$=1/(d-7)$

How do you simplify and find the excluded value of (d+7)/(d^2-49)(d+7)/(d^2-49)?