How do you simplify and find the restrictions for $(3b)/(b(b + 9))$ ?

Question

1508 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-27T12:38:24

See the solution process below:

To simplify this expression cancel the common term in the numerator and denominator:

$(3b)/(b(b + 9)) = (3color(red)(cancel(color(black)(b))))/(color(red)(cancel(color(black)(b)))(b + 9)) = 3/(b + 9)$

To find the restrictions we need to use the original form of the expression. Because we cannot divide by $0$ we must solve for:

$b(b + 9) = 0$

To solve this we solve each term for 0:

1)

$b = 0$

2)

$b + 9 = 0$

$b + 9 - color(red)(9) = 0 - color(red)(9)$

$b + 0 = -9$

$b = -9$

The restrictions are:

$b != 0$ and $b != -9$

How do you simplify and find the restrictions for (3b)/(b(b + 9))(3b)/(b(b + 9))?