How do you simplify and find the restrictions for $(6)/(x+3)$ ?

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Answer 1 · 2017-04-25T03:17:51

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The function $6/(x+3)$ will have a restricted domain at $x=-3$ .

We know this because the denominator of our function cannot be $0$ and to find what value this occurs, we set the denominator equal to $0$ such that:

$x+3=0 -> x=-3$

What this tells us that the graph will have a vertical asymptote at $x=-3$

Thus our domain for this function is: ${x| x!= -3} or (-oo,-3) uu (-3,oo)$

How do you simplify and find the restrictions for (6)/(x+3)(6)/(x+3)?