How do you simplify and restricted value of $(x^2-36)/(3x+6)$ ?

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Answer 1 · 2017-07-18T23:41:03

$((x-6)(x+6))/(3(x+2))$ ; $x != -2$

Given: $(x^2 - 36)/(3x+6)$

The numerator is the difference of squares $(a^2 - b^2) = (a - b)(a + b): (x^2 - 6^2) = (x -6)(x+6)$

Rewriting the given expression yields: $((x -6)(x+6))/(3x + 6)$

The denominator can be factored using the greatest common factor (GCF) of $3: 3(x + 2)$

Rewriting the given expression yields: $((x-6)(x+6))/(3(x+2))$

Since there is a fraction, the denominator cannot be $= 0$ . This means that $3(x + 2) != 0$ , or $x + 2 != 0$ . This occurs when $x = -2$ .

How do you simplify and restricted value of (x^2-36)/(3x+6) (x^2-36)/(3x+6) ?