How do you simplify and state the excluded values for $(3x) /( 1-3x)$ ?

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Answer 1 · 2015-07-27T22:21:43

I am afraid there is not much to simplify.

The excluded value for $x$ is when $1-3x=0=>x!=1/3$

because you may not divide by $0$ .

Answer 2 · 2015-07-27T22:27:06

Excluded value : $x=1/3$

Add and subtract $(1)$ from the numerator to get from $" "(3x)/(1-3x)" "$ to this : $(1+3x-1)/(1-3x)" "$

then to $" "(3x-1)/(1-3x) +1/(1-3x)$

Which could also be written as : $(-1*(3x-1))/((3x-1))+1/(1-3x)color(red)= color(blue)(1/(1-3x)-1)$

Now, we can see that if $(1-3x)=0$ the expression would be undefined in $RR$

So, we say that the excluded values of $x$ are those for which $(1-3x)=0$

$=>3x=1=>color(blue)(x=1/3) " "$ is the excluded value.

How do you simplify and state the excluded values for (3x) /( 1-3x)(3x) /( 1-3x)?