How do you simplify $(b^4c^6f^8)/(b^4c^3f^5)$ ?

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Answer 1 · 2017-05-13T15:26:31

$c^3f^3$

Remember that $x^a/x^b=x^(a-b)$ .

We use this for like terms (so the $b$ s together, the $c$ s, and the $f$ s)

This becomes:

$(b^4c^6f^8)/(b^4c^3f^5)=b^(4-4)c^(6-3)f^(8-5)=c^3f^3$

How do you simplify (b^4c^6f^8)/(b^4c^3f^5)(b^4c^6f^8)/(b^4c^3f^5)?