How do you simplify $(d^2-16)/( d+4)$ ?

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Answer 1 · 2018-04-04T10:53:15

$d-4$

Use the difference in two squares:

$a^2-b^2 = (a+b)(a-b)$

$=> d^2 - 16 = (d)^2 - ( 4)^2$

$=> (d-4)(d+4)$

$=>( (d-4)(d+4))/(d+4)$

Cancel out...

$=>( (d-4)cancel((d+4)))/cancel(d+4)$

$color(blue)( = d-4$

How do you simplify (d^2-16)/( d+4)(d^2-16)/( d+4)?