How do you simplify $-\frac { 28x y ^ { 0} z ^ { 4} } { 14x ^ { 7} y ^ { 5} z ^ { 4} }$ ?

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Answer 1 · 2017-06-15T05:08:54

$(28xy^0z^4)/(14x^7y^5z^4)=2/(x^6y^5)$

$(28xy^0z^4)/(14x^7y^5z^4)$

= $28/14xx x^1/x^7xxy^0/y^5xxz^4/z^4$

= $2xx x^((1-7))xxy^((0-5))xxz^((4-4))$

= $2xx x^(-6)xxy^(-5)xxz^0$

= $2xx1/x^6xx1/y^5xx1$

= $2/(x^6y^5)$

How do you simplify -\frac { 28x y ^ { 0} z ^ { 4} } { 14x ^ { 7} y ^ { 5} z ^ { 4} }-\frac { 28x y ^ { 0} z ^ { 4} } { 14x ^ { 7} y ^ { 5} z ^ { 4} }?