How do you simplify $\frac { 65x ^ { 2} x ^ { 11} y ^ { 5} y ^ { 9} } { 5x x ^ { 3} y ^ { 2} x ^ { 2} }$ ?

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Answer 1 · 2018-03-24T21:40:01

$13x^7y^2$

$(65x^2x^11y^5y^9)/(5x x^3y^2x^2) rarr$ Combine all the like terms in the numerator and the denominator first

$(65x^(2+11)y^(5+9))/(5x^(1+3+2)y^2)$

$(65x^13y^14)/(5x^6y^2)$

65 is evenly divisible by 5

$(13x^13y^14)/(x^6y^2) rarr$ Exponents can be subtracted from each other when dividing (ex. $x^6/x^2=x^(6-2)=x^4$ )

$13x^(13-6)y^(14-2)$

$13x^7y^2$

How do you simplify \frac { 65x ^ { 2} x ^ { 11} y ^ { 5} y ^ { 9} } { 5x x ^ { 3} y ^ { 2} x ^ { 2} }\frac { 65x ^ { 2} x ^ { 11} y ^ { 5} y ^ { 9} } { 5x x ^ { 3} y ^ { 2} x ^ { 2} }?