How do you simplify $\frac{6 n^{4}}{4 n^{2}}$ $\frac { 6n ^ { 4} } { 4n ^ { 2} }$ ?

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Answer 1 · 2017-06-09T05:15:07

$\frac{6 n^{4}}{4 n^{2}} = \frac{3 n^{2}}{2}$ $(6n^4)/(4n^2)=(3n^2)/2$

$\frac{6 n^{4}}{4 n^{2}}$ $(6n^4)/(4n^2)$

= $\frac{2 \times 3 \times n \times n \times n \times n}{2 \times 2 \times n \times n}$ $(2xx3xxnxxnxxnxxn)/(2xx2xxnxxn)$

= $(cancel2xx3xxcancelnxxcancelnxxnxxn)/(2xxcancel2xxcancelnxxcanceln)$

= $(3xxnxxn)/2$

= $(3n^2)/2$

How do you simplify \frac { 6n ^ { 4} } { 4n ^ { 2} }6n44n2\frac { 6n ^ { 4} } { 4n ^ { 2} }?