How do you simplify $\frac{8 c d^{4}}{2 c d^{8} \cdot c d \cdot c^{6} d}$ $\frac { 8c d ^ { 4} } { 2c d ^ { 8} \cdot c d \cdot c ^ { 6} d }$ ?

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Answer 1 · 2017-06-02T07:25:54

$\frac{8 c d^{4}}{2 c d^{8} \cdot c d \cdot c^{6} d} = \frac{4}{c^{7} d^{6}}$ $(8cd^4)/(2cd^8*cd*c^6d)=4/(c^7d^6)$

$\frac{8 c d^{4}}{2 c d^{8} \cdot c d \cdot c^{6} d}$ $(8cd^4)/(2cd^8*cd*c^6d)$

= $\frac{8 c d^{4}}{2 c \times c \times c^{6} \times d^{8} \times d \times d}$ $(8cd^4)/(2cxxcxxc^6xxd^8xxd xxd)$

= $\frac{8 c d^{4}}{2 c^{(1 + 1 + 6)} \times d^{(8 + 1 + 1)}}$ $(8cd^4)/(2c^((1+1+6))xxd^((8+1+1))$

= $\frac{8 c d^{4}}{2 c^{8} \times d^{10}}$ $(8cd^4)/(2c^8xxd^10)$

= $\frac{8}{2} \times \frac{c}{c^{8}} \times \frac{d^{4}}{d^{10}}$ $8/2xxc/c^8xxd^4/d^10$

= $4 \times \frac{1}{c^{(8 - 1)}} \times \frac{1}{d^{(10 - 4)}}$ $4xx1/c^((8-1))xx1/d^((10-4))$

= $4 \times \frac{1}{c^{7}} \times \frac{1}{d^{6}}$ $4xx1/c^7xx1/d^6$

= $\frac{4}{c^{7} d^{6}}$ $4/(c^7d^6)$

How do you simplify \frac { 8c d ^ { 4} } { 2c d ^ { 8} \cdot c d \cdot c ^ { 6} d }8cd42cd8⋅cd⋅c6d\frac { 8c d ^ { 4} } { 2c d ^ { 8} \cdot c d \cdot c ^ { 6} d }?