Question

How do you simplify `\frac{a^{-2}b^{-3}}{c^{-1}}` without any negative or fractional exponents in the answer?

Answer 1

Well, I am not completely sure it is what you want but here it is: `c/(a^2b^3)`

what happens is that a negative exponent allows you to "change floor" to your factor in a fraction.
So if you have:
`a^(-2)` it can go "downstairs" to the denominator loosing the minus sign: `1/(a^2)`;
Same thing with `b^(-3)` that becomes: `1/(b^3)`;
If the factor is already "downstairs", in the denominator, you can take it "upstairs" to the numerator, loosing again the minus sign.
`1/(c^(-1)` becomes: `c^1=c`.