How do you simplify $(g^0h^7j^-2)/(g^-5h^0j^-2)$ ?

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Answer 1 · 2017-03-02T13:58:52

See the entire simplification process below:

The first step I would take is to rewrite this expression as:

$(g^0/g^-5)(h^7/h^0)(j^-2/j^-2)$

We can use this rule of exponents to simplify this expression:

$a^color(red)(0) = 1$

And, we know $x/x = 1$ therefore $J^-2/j^-2 = 1$

So we can again rewrite the expression as:

$(1/g^-5)(h^7/1)(1) = h^7/g^-5$

We can eliminate the negative exponent by using this rule for exponents: $1/x^color(red)(a) = x^color(red)(-a)$

$h^7/(g^color(red)(-5)) = h^7g^color(red)(- -5) = h^7g^5$

How do you simplify (g^0h^7j^-2)/(g^-5h^0j^-2)(g^0h^7j^-2)/(g^-5h^0j^-2)?