How do you simplify $(m^7n^4p)/(m^3n^3p)$ ?

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Answer 1 · 2017-01-18T18:48:39

$m^4n$ (if $m, n,p,$ are all non-zero)

We know that $a^m/a^n = a^(m-n)$ , for $a!=0$ .

So, provided $m, n,p,$ are all non-zero, the result is:

$m^7/m^3 n^4/n^3 p/p = m^4n$

How do you simplify (m^7n^4p)/(m^3n^3p)(m^7n^4p)/(m^3n^3p)?