How do you simplify $(n^4q^4w^6)/(q^2n^3w)$ ?

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Answer 1 · 2017-05-01T22:34:17

You may rewrite: $=n^4/n^3xxq^4/q^2xxw^6/w$

You may write out the powers and cancel. You may also realize that

$x^a/x^b=x^(a-b)$

$=n^(4-3)xxq^(4-2)xxw^(6-1)=n^1xxq^2xxw^5=nq^2w^5$

How do you simplify (n^4q^4w^6)/(q^2n^3w)(n^4q^4w^6)/(q^2n^3w)?