How do you simplify $(r^-2)^4$ and write it using only positive exponents?

Question

1496 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-09-03T13:04:51

$(r^(-2))^4=1/r^8$

We can write $a^(-m)=1/a^m$ , as $a^(-m)×a^m=a^(-m+m)=a^0=1$ and hence $a^(-m)=1/a^m$ .

Therefore $(r^(-2))^4$

= $r^(-2×4)$

= $r^(-8)$

= $1/r^8$

How do you simplify (r^-2)^4(r^-2)^4 and write it using only positive exponents?