How do you simplify $(s^-3 t^-5)/(s^2 t^3)^-1$ ?

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Answer 1 · 2015-05-18T20:34:36

By exponential rules, we have that $n^-1=1/n$

Considering so, we have:

$(1/(s^3t^5))/(1/(s^2t^3))=(s^2t^3)/(s^3t^5)$

Another exponential rule states that $a^n/a^m=a^(n-m)$ .

$s^-1t^-2=1/(s*t^2)$

How do you simplify (s^-3 t^-5)/(s^2 t^3)^-1(s^-3 t^-5)/(s^2 t^3)^-1?