Question

How do you simplify `(sinxcosx)/(1-sin^2x)`?

I got `cotx` as an answer... don't know if it is right though...

Answer 1

`(sinx*cosx)/(1-sin^2x)==tanx`

Explanation:

`(sinx*cosx)/(1-sin^2x)=(sinx*cosx)/cos^2x=sinx/cosx=tanx`

Answer 2

See the answer below...

Explanation:

`(sinxcosx)/(1-sin^2x)=(sinxcosx)/cos^2x`[BECAUSE `color(red)(sin^2x+cos^2x=1`]
`color(white)(mmmmfG)=(sinxcancelcosx)/(cosxcdotcancelcosx)=color(red)(tanx`

So the answer is `color(brown)(tanx`

Hope it helps...
Thank you...