How do you simplify the expression $1 + 7 \sqrt{z - 1}$ $1+7sqrt(z-1)$ for $z = 290$ $z=290$ ?

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How do you simplify the expression $1 + 7 \sqrt{z - 1}$ $1+7sqrt(z-1)$ for $z = 290$ $z=290$ ?

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Answer 1 · 2017-02-18T21:37:57

$120$ $120$

Explanation:

Substitute z = 290 into the expression.

$1 + 7 \sqrt{290 - 1}$ $1+7sqrt(color(red)(290)-1)$

$= 1 + 7 \sqrt{289}$ $=1+7sqrt289$

$= 1 + (7 \times 17) since \sqrt{289} = 17$ $=1+(7xx17)" since " sqrt289=17$

$= 1 + 119$ $=1+119$

$= 120$ $=120$

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How do you simplify the expression $1 + 7 \sqrt{z - 1}$ $1+7sqrt(z-1)$ for $z = 290$ $z=290$ ?

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How do you simplify the expression $1 + 7 \sqrt{z - 1}$ $1+7sqrt(z-1)$ for $z = 290$ $z=290$ ?