How do you simplify the expression $\frac{b^{3} a^{5}}{b^{2} a^{4}}$ $(b^3 a^5)/(b^2 a^4)$ ?

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Answer 1 · 2016-03-26T22:03:58

$\frac{b^{3} a^{5}}{b^{2} a^{4}} = b a$ $(b^3a^5)/(b^2a^4)=ba$

Consider the example of $\frac{1}{x^{3}}$ $1/(x^3)$ This may be written as $x^{- 3}$ $x^(-3)$

Ok, so lets look at your question. You have as the denominator :

$\frac{1}{b^{2} a^{4}}$ $1/(b^2a^4)$ this can be written as: $b^{- 2} a^{- 4}$ $" "b^(-2)a^(-4)$

Putting this together with the numerator we have

$b^{3} a^{5} \times b^{- 2} a^{- 4}$ $b^3a^5xxb^(-2)a^(-4)$

This gives us:

$b^{3 - 2} a^{5 - 4} = b^{1} a^{1}$ $b^(3-2)a^(5-4)" "=" "b^1a^1$

This is the same as: $b a$ $" "ba$

How do you simplify the expression (b^3 a^5)/(b^2 a^4)b3a5b2a4(b^3 a^5)/(b^2 a^4)?