How do you simplify $\frac{x + 1}{3} = \frac{2 x - 1}{4}$ $(x+1)/3 = (2x-1)/4$ ?

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How do you simplify $\frac{x + 1}{3} = \frac{2 x - 1}{4}$ $(x+1)/3 = (2x-1)/4$ ?

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Answer 1 · 2015-11-11T20:43:16

If you want to simplify it, you can write it as $4 x + 4 = 6 x - 3$ $4x+4=6x-3$ after cross multiplication. This can be rearranged to $2 x = 7$ $2x=7$ or $x = \frac{7}{2}$ $x=7/2$ . This last answer is also the solution of the original equation.

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How do you simplify $\frac{x + 1}{3} = \frac{2 x - 1}{4}$ $(x+1)/3 = (2x-1)/4$ ?

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How do you simplify $\frac{x + 1}{3} = \frac{2 x - 1}{4}$ $(x+1)/3 = (2x-1)/4$ ?