How do you simplify $(x^2-16)/(3x^2+10x-8)$ ?

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Answer 1 · 2016-09-04T17:21:08

$(x-4)/(3x-2)$ .

The Expression $=(x^2-16)/(3x^2+10x-8)$

$={(x-4)(x+4)}/{ul(3x^2+12x)-ul(2x-8)}$

$={(x-4)(x+4)}/{3x(x+4)-2(x+4)}$

$={(x-4)cancel((x+4))}/{(3x-2)cancel((x+4))}$

$=(x-4)/(3x-2)$ .

Answer 2 · 2016-09-04T17:27:24

$((x-4))/((3x-2))$

In an algebraic fraction, only factors can be cancelled.

Find the factors in the numerator and denominator.

$(x^2 -16)/(3x^2 +10x -8) " " (larr"difference of squares")/(larr"quadratic trinomial")$

= $(cancel(x+4)(x-4))/((3x-2)cancel(x+4)) = ((x-4))/((3x-2))$

How do you simplify (x^2-16)/(3x^2+10x-8) (x^2-16)/(3x^2+10x-8) ?