How do you simplify $(x^2-2x-8)/(x^2+3x-4)$ ?

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Answer 1 · 2015-09-14T00:43:41

It is already simplified.

You factor the trimonial in the numerator, and the denominator.

$((x - 4) (x + 2))/((x - 1) (x + 4))$

As you can see, there are no factors that are the same. So it is already as simple as it can be.

How do you simplify (x^2-2x-8)/(x^2+3x-4)(x^2-2x-8)/(x^2+3x-4)?