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How do you simplify ${(x^{\frac{2}{3}} \cdot x^{\frac{4}{6}})}^{- 3}$ $(x^(2/3)*x^(4/6))^(-3)$ ?

1 Answer

Jan 29, 2015

Simplify the fractions -> ${(x^{\frac{2}{3}} \cdot x^{\frac{2}{3}})}^{- 3}$ $(x^(2/3)*x^(2/3))^(-3)$
Multiplying with same bases, add exponents -> ${(x^{\frac{4}{3}})}^{- 3}$ $(x^(4/3))^(-3)$
Power to a power, multiply exponents -> $x^{- 4}$ $x^(-4)$

Finally, $x^{- 4}$ $x^(-4)$ = $\frac{1}{x^{4}}$ $1/x^4$

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