How do you simplify $(x^{2} + 3 x) - (x^{2} + 2 x + 3)$ $(x^2+ 3x) - (x^2+ 2x + 3)$ ?

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Answer 1 · 2018-03-04T03:32:48

The answer is $x - 3$ $x-3$ .

$(x^{2} + 3 x) - (x^{2} + 2 x + 3)$ $(x^2+3x)-(x^2+2x+3)$

Remove the unnecessary brackets.
$= x^{2} + 3 x - (x^{2} + 2 x + 3)$ $=x^2+3x-(x^2+2x+3)$

When there is a "-" sign in front of the bracket, change the sign of term in the bracket.
$= x^{2} + 3 x - x^{2} - 2 x - 3$ $=x^2+3x-x^2-2x-3$

Eliminate the opposites.
$= 3 x - 2 x - 3$ $=3x-2x-3$

Collect the like terms.
$= x - 3$ $=x-3$

Hope this helped, it might be a little confusing.

How do you simplify (x2+3x)−(x2+2x+3)(x^2+ 3x) - (x^2+ 2x + 3)?