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How do you simplify $\frac{x^{2} - 9}{x^{2} + 3 x}$ $(x^2-9)/(x^2+3x)$ ?

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Konstantinos Michailidis

Sep 16, 2015

We have that $\frac{x^{2} - 9}{x^{2} + 3 x} = \frac{(x - 3) (x + 3)}{x (x + 3)} = \frac{x - 3}{x}$ $(x^2-9)/(x^2+3x)=((x-3)(x+3))/(x(x+3))=(x-3)/x$

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