How do you simplify $(x^3-27)/(x^3+3x^2+9x)$ ?

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Answer 1 · 2016-11-06T21:23:46

$= (x-3)/x$

Before you can simplify an algebraic fraction such as this one, you should find the factors first.

$(("difference of cubes")rarr)/(("common factor of x")rarr) (x^3 -27)/(x^3+3x^2+9x)$

$=((x-3)cancel((x^2+3x+9)))/(xcancel((x^2+3x+9))$

$= (x-3)/x$

How do you simplify (x^3-27)/(x^3+3x^2+9x)(x^3-27)/(x^3+3x^2+9x)?