How do you simplify $(x^3+3x^2-2x-6)/(x^3+27)$ ?

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Answer 1 · 2016-09-05T18:21:24

$(x^2-2)/(x^2-3x+9)$ .

The Expression $={ul(x^3+3x^2)-ul(2x-6)}/{(x+3)(x^2-3x+9)}$

$={x^2(x+3)-2(x+3)}/{(x+3)(x^2-3x+9)}$

$={cancel((x+3))(x^2-2)}/{cancel((x+3))(x^2-3x+9)}$

$=(x^2-2)/(x^2-3x+9)$ .

How do you simplify (x^3+3x^2-2x-6)/(x^3+27)(x^3+3x^2-2x-6)/(x^3+27)?